Wheatley's Trajectory
Quote from FelixGriffin on September 24, 2013, 5:33 pmDuring a period of boredom earlier I decided to try and simulate the physics of opening a portal on the moon. Assuming that a portal has an area of roughly two square meters (the player is a bit under 128 units, the physical opening of the portal is really a 64x128 rectangle) and that the air pressure on Earth will take a very long time to drop off, I can plug into the choked flow equations and get:
Then use the equation Velocity = Mass Flow / (Density * Area) and it seems that all the air (and Wheatley and the Space Core and Rick and the Portal Gun...) is being launched into space at 197.67 meters per second.
This is an order of magnitude less than the moon's escape velocity, so Wheatley isn't coming back to Earth. It's also too low to go into a stable orbit. So he'll crash into the moon again at some point.
My question is, now, does anyone know of a good way to calculate his trajectory? It seems that the portal opened normal to the vector from the Earth to the moon, so in the absence of the Earth he's just crash right into the place where the portal was. But the rotation and orbit of the moon might mess that up.
Any thoughts?
During a period of boredom earlier I decided to try and simulate the physics of opening a portal on the moon. Assuming that a portal has an area of roughly two square meters (the player is a bit under 128 units, the physical opening of the portal is really a 64x128 rectangle) and that the air pressure on Earth will take a very long time to drop off, I can plug into the choked flow equations and get:
Then use the equation Velocity = Mass Flow / (Density * Area) and it seems that all the air (and Wheatley and the Space Core and Rick and the Portal Gun...) is being launched into space at 197.67 meters per second.
This is an order of magnitude less than the moon's escape velocity, so Wheatley isn't coming back to Earth. It's also too low to go into a stable orbit. So he'll crash into the moon again at some point.
My question is, now, does anyone know of a good way to calculate his trajectory? It seems that the portal opened normal to the vector from the Earth to the moon, so in the absence of the Earth he's just crash right into the place where the portal was. But the rotation and orbit of the moon might mess that up.
Any thoughts?
Quote from User on September 24, 2013, 5:49 pmOmg, you really try to calculate Wheatleys fly through space? Didnt thought that someone would ever do that
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But your question, no Idea..
Omg, you really try to calculate Wheatleys fly through space? Didnt thought that someone would ever do that
But your question, no Idea..
Quote from FelixGriffin on September 24, 2013, 11:06 pmIn layman's terms, the mass of the air rushing past every second is the area of the portal times the square root of a bunch of stuff. The main ones are the air pressure in Michigan this afternoon (1021) and the density of the air (1.225). The 1.4 just has to do with the way air moves. The result is 434.3 kilograms every second. If we divide that by the density of the air and the area of the portal we get how fast the air is moving, and I assumed Wheatley's velocity would be the same (which isn't quite accurate but is good enough for now).
In better layman's terms, speedy air go in, speedy air come out.
In layman's terms, the mass of the air rushing past every second is the area of the portal times the square root of a bunch of stuff. The main ones are the air pressure in Michigan this afternoon (1021) and the density of the air (1.225). The 1.4 just has to do with the way air moves. The result is 434.3 kilograms every second. If we divide that by the density of the air and the area of the portal we get how fast the air is moving, and I assumed Wheatley's velocity would be the same (which isn't quite accurate but is good enough for now).
In better layman's terms, speedy air go in, speedy air come out.

Quote from Gemarakup on September 25, 2013, 1:27 amYes, and because there are not enough forces in space, Wheatley can't just stop where he is and he doesn't have a way to force controlled movement, so he should keep speeding in space and he can't speak in space because there's no matter in space.
Yes, and because there are not enough forces in space, Wheatley can't just stop where he is and he doesn't have a way to force controlled movement, so he should keep speeding in space and he can't speak in space because there's no matter in space.
Quote from Tmast98 on September 25, 2013, 2:34 amFelixGriffin wrote:In better layman's terms, speedy air go in, speedy air come out.YAY. I can understand now!
YAY. I can understand now!

Quote from Gemarakup on September 25, 2013, 2:57 amUnfortunately, it doesn't seem like the moon has enough gravity to turn that air into an atmosphere, and I'm anyway not going to start breathing neurotoxic gas.
Unfortunately, it doesn't seem like the moon has enough gravity to turn that air into an atmosphere, and I'm anyway not going to start breathing neurotoxic gas.
Quote from FelixGriffin on September 26, 2013, 11:02 pmOkay, new problem I just noticed: why did the portal close after GLaDOS pulled you in? The portal gun couldn't have hit a fizzler, it was leaving the moon at 197.67 meaters per second. And it's not a range limit or you couldn't have opened the moon portal.
Okay, new problem I just noticed: why did the portal close after GLaDOS pulled you in? The portal gun couldn't have hit a fizzler, it was leaving the moon at 197.67 meaters per second. And it's not a range limit or you couldn't have opened the moon portal.
Quote from Habzs on September 27, 2013, 4:50 amFelixGriffin wrote:Okay, new problem I just noticed: why did the portal close after GLaDOS pulled you in? The portal gun couldn't have hit a fizzler, it was leaving the moon at 197.67 meaters per second. And it's not a range limit or you couldn't have opened the moon portal.Maybe she washed the paint off?
Maybe she washed the paint off?

Quote from TeamSpen210 on September 27, 2013, 6:49 amI'm assuming she remote-fizzled it or moved the panel around.
I'm assuming she remote-fizzled it or moved the panel around.
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