Then use the equation Velocity = Mass Flow / (Density * Area) and it seems that all the air (and Wheatley and the Space Core and Rick and the Portal Gun...) is being launched into space at 197.67 meters per second.
This is an order of magnitude less than the moon's escape velocity, so Wheatley isn't coming back to Earth. It's also too low to go into a stable orbit. So he'll crash into the moon again at some point.
My question is, now, does anyone know of a good way to calculate his trajectory? It seems that the portal opened normal to the vector from the Earth to the moon, so in the absence of the Earth he's just crash right into the place where the portal was. But the rotation and orbit of the moon might mess that up.
Any thoughts?


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